NCERT SOLUTIONS FOR CLASS 10 MATHS INTRODUCTION TO TRIGONOMETRY CHAPTER 8 EX 8.3

NCERT SOLUTIONS FOR CLASS 10 MATHS INTRODUCTION TO TRIGONOMETRY CHAPTER 8 EX 8.3

Question 1.
Evaluate:
NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3 Q1
Solution:
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.3 Free PDF Download

Ex 8.3 Class 10 Maths Question 2.
Show that:
(i) tan 48° tan 23° tan 42° tan 67° = 1
(ii) cos 38° cos 52° – sin 38° sin 52° = 0
Solution:
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.3 Free PDF Q2

Ex 8.3 Class 10 Maths Question 3.
If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.
Solution:
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.3 Q3

Ex 8.3 Class 10 Maths Question 4.
If tan A = cot B, prove that A + B = 90°.
Solution:
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.3 PDF Q4

Ex 8.3 Class 10 Maths Question 5.
If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A.
Solution:
Exercise 8.3 Class 10 NCERT Solutions Chapter 8 Trigonometry PDF Download Q5

Ex 8.3 Class 10 Maths Question 6.
If A, B and C are interior angles of a triangle ABC, then show that: sin (B+C2) = cos A2
Solution:
Exercise 8.3 Class 10 NCERT Solutions Chapter 8 Trigonometry PDF Q6

Ex 8.3 Class 10 Maths Question 7.
Express sin 61° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
Solution:
Trigonometry Class 10 Chapter 8 Exercise 8.3 NCERT Solutions Q7