Q 1 – In a data, if l = 40, h = 15, f1=7, f0=3, f2=6, then the mode is
(a) 52
(b) 62
(c) 72
(d) none of these
(a) 52
Q 2 – Cumulative frequency curve is also called
(a) histogram
(b) ogive
(c) bar graph
(d) median
(b) ogive
Q 3 – The mode of 4, 5, 6, 8, 5, 4, 8, 5, 6, x, 8 is 8. The value of ‘x’ is
(a) 4
(b) 5
(c) 6
(d) 8
(d) 8
Q 4 – The relationship between mean, median and mode for a moderately skewed distribution is
(a) mode = median – 2 mean
(b) mode = 3 median – 2 mean
(c) mode = 2 median – 3 mean
(d) mode = median – mean
(b) mode = 3 median – 2 mean
Q 5 – The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 3, 1, 3, 2, 3. The mode of the data is
(a) 1
(b) 2
(c) 3
(d) 4
(c) 3
Q 6 – The algebraic sum of the deviations of a frequency distribution from its mean is always,
(a) greater than zero
(b) less than zero
(c) zero
(d) a non-zero number
(c) zero
Q 7 – The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observations of the set is increased by 2, then the median of the new set
(a) is increased by 2
(b) is decreased by 2
(c) are two times the original number
(d) Remains the same as that of the original set.
(d) Remains the same as that of the original set.
Q 8 – For the following distribution
| Monthly Expenditure (?) | No. of families |
| Expenditure less than ? 10,000 | 15 |
| Expenditure less than? 13,000 | 31 |
| Expenditure less than ? 16,000 | 50 |
| Expenditure less than ? 19,000 | 67 |
| Expenditure less than ? 22,000 | 85 |
| Expenditure less than ? 25,000 | 100 |
The number of families having expenditure range (in ?) 16,000 19,000 is
(a) 15
(b) 16
(c) 17
(d) 19
(c) 17
Q 9 – Mode and mean of data are 12k and 15A. Median of the data is
(a) 12k
(b) 14k
(c) 15k
(d) 16k
(b) 14k
Q 10 – Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is
(a) 48
(b) 49
(c) 50
(d) 60
(c) 50
Q 11 – For the following distribution
| Marks obtained | No. of students |
| More than or equal to 0 | 63 |
| More than or equal to 10 | 58 |
| More than or equal to 20 | 55 |
| More than or equal to 30 | 51 |
| More than or equal to 40 | 48 |
| More than or equal to 50 | 42 |
the frequency of class 20-30 is
(a) 35
(b) 4
(c) 48
(d) 51
(b) 4
Q 12 – The times, in seconds, taken by 150 atheletes to run a 110 m hurdle race are tabulated below:
| Class | Frequency |
| 13.8 – 14.0 | 2 |
| 14.0 – 14.2 | 4 |
| 14.2 – 14.4 | 5 |
| 14.4 – 14.6 | 71 |
| 14.6 – 14.8 | 48 |
| 14.8 – 15.0 | 20 |
The number of athletes who completed the race in less than 14.6 seconds is:
(a) 11
(b) 71
(c) 82
(d) 130
(c) 82
Q 13 – If x1, x2, x3,….., xn are the observations of a given data. Then the mean of the observations will be:
(a) Sum of observations/Total number of observations
(b) Total number of observations/Sum of observations
(c) Sum of observations+Total number of observations
(d) None of the above
(a) Sum of observations/Total number of observations
Q 14 – The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its
(a) mean
(b) median
(c) mode
(d) all the three above
(b) median
Q 15 – The age of 18 students of a class is reported below. Their modal age is 10, 17, 14, 10, 11, 12, 12, 13, 17, 13, 14, 14, 15, 16, 17, 15, 17, 16
(a) 22 years
(b) 17 years
(c) 14 years
(d) 16 years
(b) 17 years
Q 16 – Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is
(a) 48
(b) 49
(c) 50
(d) 60
(c) 50
Q 17 – If the mean of first n natural numbers is 3n/5, then the value of n is:
(a) 3
(b) 4
(c) 5
(d) 6
(c) 5
Q 18 – For the following distribution
| Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| No. of Students | 3 | 9 | 13 | 10 | 5 |
the number of students who got marks less than 30 is
(a) 13
(b) 25
(c) 10
(d) 12
(b) 25
Q 19 – The mean and the median of distribution are 45.9 and 46 respectively. The mode will be
(a) 45
(b) 47
(c) 48
(d) 46.2
(d) 46.2
Q 20 – For the following distribution
| Marks | No. of students |
| Less than 20 | 4 |
| Less than 40 | 12 |
| Less than 60 | 25 |
| Less than 80 | 56 |
| Less than 100 | 74 |
| Less than 120 | 80 |
the modal class is
(a) 20 – 40
(b) 40 – 60
(c) 60 – 80
(d) 80 -100
(c) 60 – 80
Q 21 – If AM of a, a + 3, a + 6, a + 9 and a + 12 is 10, then a is equal to;
(a) 1
(b) 2
(c) 3
(d) 4
(d) 4
Q 22 – While computing mean of grouped data, we assume that the frequencies are
(a) centered at the upper limits of the classes
(b) centred at the lower limits of the classes
(c) centred at the classmarks of the classes
(d) evenly distributed over all the classes
(c) centered at the classmarks of the classes
Q 23 – The perimeter of circular and square fields are equal. If the area of the square field is 484 m² then the diameter of the circular field is
(a) 14 m
(b) 21 m
(c) 28 m
(d) 7 m
(c) 28 m
Q 24 – Which of the following can not be determined graphically?
(a) Mean
(b) Median
(c) Mode
(d) None of these
(a) Mean
Q 25 – The median of the first 10 prime numbers is
(a) 11
(b) 12
(c) 13
(d) none of these
(b) 12
Q 26 – Mode is the
(a) middlemost frequent value
(b) least frequent value
(c) maximum frequent value
(d) none of these
(c) maximum frequent value
Q 27 – The mean of the first 10 natural numbers is
(a) 5
(b) 6
(c) 4.5
(d) 5.5
(d) 5.5
Q 28 – The class interval of a given observation is 10 to 15, then the classmark for this interval will be:
(a) 11.5
(b) 12.5
(c) 12
(d) 14
(b) 12.5
Q 29 – If the sum of frequencies is 24, then the value of x in the observation: x, 5,6,1,2, will be;
(a) 4
(b) 6
(c) 8
(d) 10
(d) 10
Q 30 – Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is
(a) 48
(b) 49
(c) 50
(d) 60
(c) 50